Tidyverse 🪐to Polars 🐻‍❄️: My Notes

I found Polars syntax is quite similar to dplyr. And the way that we can chain the functions makes it even more familiar! It was fun learning the nuances, now it’s time to put them into practice! Wish me luck! 🍀

Motivation < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

In preparation for using more Python in 2025 and also to speak more of the same language with our datathon team, I’ve decided to practice Polars in Python thinking in R first. Below is my notes to myself, hopefully I’ll be able to refer back and improve this more as I use more of this for the next month. Wish me luck!

Objectives < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

• Create A Dataframe
• Filter, Select, Summarize, Across
• Mutate, Paste
• Extract
• Case_when
• Join / Merge
• To Dummies/Pivot/Unpivot
• Helpful Resources
• Lessons Learnt

Create A Dataframe < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

Tidyverse

library(tidyverse)
library(reticulate)
use_virtualenv('path/to/your/environment')

df <- tibble(
  name = c("Alice", "Bob", "Charlie", "Ken", "Steven", "Carlos"),
  age = c(30, 25, 35, 50, 60, 58),
  city = c("New York", "San Francisco", "Tokyo", "Toronto", "Lima", "Cleveland"),
  address = c("123 Main St, Ontario, OH", "123 Main St, Calgary, AB", "456-7890, Tokyo, NY",
              "49494 Exchange St, Toronto, ON", "1010 Gb st, Lima, OH", "666 Heaven dr, Cleveland, OH"),
  phone_number = c("123-456-7890", "987-654-3210", "098-765-4332", "111-232-4141", 
                  "505-402-6060", "909-435-1000"),
  email = c("alice@example.com", "bob@example.com", "charlie@example.com", 
            "ken@stats.org", "stephencurry@nba.com", "carlos@genius.edu"),
  salary = c(50000, 45000, 60000, 20000, 40000, 30000),
  department = c("Engineering", "Marketing", "Finance", "Marketing", "Marketing", "Finance"),
  hire_date = c("2010-01-01", "2012-05-15", "2015-10-01", "2010-04-01", 
                "2009-10-30", "2005-11-12"),
  status = c("Active", "Inactive", "Active", "Inactive", "Active", "Active"),
  salary_increase_percentage = c(10, 5, 15, 10, 10, 5),
  years_of_service = c(5, 3, 7, 10, 10, 12),
  bonus_amount = c(2000, 1500, 3000, 5000, 3000, 2000),
  performance_rating = c(4, 3, 5, 5, 4, 4),
  performance_reviews_count = c(2, 1, 3, 3, 4, 5),
  performance_reviews_last_updated = c("2022-05-01", "2021-07-15", "2022-08-31",
                                     "2024-10-30", "2023-01-02", "2024-12-12")
)

Polars

import polars as pl

df = pl.DataFrame({
    "name": ["Alice", "Bob", "Charlie","Ken","Steven","Carlos"],
    "age": [30, 25, 35, 50, 60, 58],
    "city": ["New York", "San Francisco", "Tokyo","Toronto","Lima","Cleveland"],
    "address" : ["123 Main St, Ontario, OH","123 Main St, Calgary, AB", "456-7890, Tokyo, NY","49494 Exchange St, Toronto, ON","1010 Gb st, Lima, OH","666 Heaven dr, Cleveland, OH"],
    "phone_number" : ["123-456-7890", "987-654-3210", "098-765-4332","111-232-4141","505-402-6060","909-435-1000"],
    "email" : ["alice@example.com", "bob@example.com", "charlie@example.com","ken@stats.org","stephencurry@nba.com","carlos@genius.edu"],
    "salary" : [50000, 45000, 60000,20000,40000,30000],
    "department" : ["Engineering", "Marketing", "Finance","Marketing","Marketing","Finance"],
    "hire_date" : ["2010-01-01", "2012-05-15", "2015-10-01", "2010-04-01","2009-10-30","2005-11-12"],
    "status" : ["Active", "Inactive", "Active","Inactive","Active","Active"],
    "salary_increase_percentage" : [10, 5, 15,10,10,5],
    "years_of_service" : [5, 3, 7,10,10,12],
    "bonus_amount" : [2000, 1500, 3000,5000,3000,2000],
    "performance_rating" : [4, 3, 5, 5, 4, 4],
    "performance_reviews_count" : [2, 1, 3, 3, 4, 5],
    "performance_reviews_last_updated" : ["2022-05-01", "2021-07-15", "2022-08-31", "2024-10-30","2023-01-02","2024-12-12"]
})

Filter, Select, Summarize, Across < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

• Filter records where age is greater and equal to 30
• return columns with name:address, and columns that starts with performance* and salary*
• return mean of values across all numeric data

Tidyverse

df |>
  filter(age >= 30) |>
  select(1:3, starts_with("performance"), starts_with("salary")) |> 
  summarize(across(.cols = where(is.numeric), .fns = mean, .names = "mean_{.col}"))

## # A tibble: 1 × 5
##   mean_age mean_performance_rating mean_performance_reviews_count mean_salary
##      <dbl>                   <dbl>                          <dbl>       <dbl>
## 1     46.6                     4.4                            3.4       40000
## # ℹ 1 more variable: mean_salary_increase_percentage <dbl>

Polars

df \
    .filter(pl.col('age') >= 30) \
    .select(df.columns[0:4]+['^performance.*$','^salary.*$']) \
    .select(pl.col(pl.Int64).mean().name.prefix('mean_'))

For some reason, for the regex above, I have to use ^ and $ sandwiched to return those column nams that I want to include. bizzare.

Mutate, Paste < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

Test 1

• make a new column called combination_of_character
• paste all columns with character datatype separated by “, a space
• select the created column

Tidyverse

df |>
  rowwise() |>
  transmute(combination_of_character = paste(
      across(where(is.character)), 
      collapse = " "
    )) |>
  select(combination_of_character)

## # A tibble: 6 × 1
## # Rowwise: 
##   combination_of_character                                                      
##   <chr>                                                                         
## 1 Alice New York 123 Main St, Ontario, OH 123-456-7890 alice@example.com Engine…
## 2 Bob San Francisco 123 Main St, Calgary, AB 987-654-3210 bob@example.com Marke…
## 3 Charlie Tokyo 456-7890, Tokyo, NY 098-765-4332 charlie@example.com Finance 20…
## 4 Ken Toronto 49494 Exchange St, Toronto, ON 111-232-4141 ken@stats.org Marketi…
## 5 Steven Lima 1010 Gb st, Lima, OH 505-402-6060 stephencurry@nba.com Marketing …
## 6 Carlos Cleveland 666 Heaven dr, Cleveland, OH 909-435-1000 carlos@genius.edu …

Polars

df \
    .with_columns(
        pl.concat_str(
            pl.col(pl.String), separator=" "
        ).alias('combination_of_character')
    ) \
    .select(pl.col('combination_of_character'))

Tidyverse

Test 2

• make a new column called age_salary
• glue column age and salary together with - between
• select columns name and age_salary

df |> 
  mutate(age_salary = paste0(age, "-", salary)) |>
  select(name, age_salary)

## # A tibble: 6 × 2
##   name    age_salary
##   <chr>   <chr>     
## 1 Alice   30-50000  
## 2 Bob     25-45000  
## 3 Charlie 35-60000  
## 4 Ken     50-20000  
## 5 Steven  60-40000  
## 6 Carlos  58-30000

Polars

df \
    .with_columns(
        age_salary=pl.format('{}-{}',pl.col('age'),pl.col('salary'))
    ) \
    .select(pl.col('name','age_salary'))

If it’s just 1 column, you can use this format age_salary= to name the column, otherwise you’d have to use alias to name it if there are multple columns

Extract < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

• create a new column area_code_and_salary
• paste street number (extract it from address) with a space and the the column salary
• select area_code_and_salary

Tidyverse

df |>
  mutate(area_code_and_salary = paste0(str_extract(address, "\\d{0,5}"), " ", salary)) |>
  select(area_code_and_salary)

## # A tibble: 6 × 1
##   area_code_and_salary
##   <chr>               
## 1 123 50000           
## 2 123 45000           
## 3 456 60000           
## 4 49494 20000         
## 5 1010 40000          
## 6 666 30000

Polars

df \
    .select(
        pl.concat_str(
            pl.col('address').str.extract(r'^(\d{0,5})'),
            pl.lit(" "),
            pl.col('salary')
        ).alias('area_code_and_salary')
    )

Have to use pl.lit(' ') for any constant string

Case_when < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

Test 1

• create a new column called familiarity
• if address contains OH, then return local
• if address contains NY, then return foodie
• otherwise return elsewhere

Tidyverse

df |>
  mutate(familiarity = case_when(
    str_detect(address, "OH") ~ "local",
    str_detect(address, "NY") ~ "foodie",
    TRUE ~ "elsewhere"
  )) 

## # A tibble: 6 × 17
##   name      age city      address phone_number email salary department hire_date
##   <chr>   <dbl> <chr>     <chr>   <chr>        <chr>  <dbl> <chr>      <chr>    
## 1 Alice      30 New York  123 Ma… 123-456-7890 alic…  50000 Engineeri… 2010-01-…
## 2 Bob        25 San Fran… 123 Ma… 987-654-3210 bob@…  45000 Marketing  2012-05-…
## 3 Charlie    35 Tokyo     456-78… 098-765-4332 char…  60000 Finance    2015-10-…
## 4 Ken        50 Toronto   49494 … 111-232-4141 ken@…  20000 Marketing  2010-04-…
## 5 Steven     60 Lima      1010 G… 505-402-6060 step…  40000 Marketing  2009-10-…
## 6 Carlos     58 Cleveland 666 He… 909-435-1000 carl…  30000 Finance    2005-11-…
## # ℹ 8 more variables: status <chr>, salary_increase_percentage <dbl>,
## #   years_of_service <dbl>, bonus_amount <dbl>, performance_rating <dbl>,
## #   performance_reviews_count <dbl>, performance_reviews_last_updated <chr>,
## #   familiarity <chr>

Polars

df \
    .with_columns([  
        pl.when(pl.col('address').str.contains('OH'))
        .then(pl.lit('local'))
        .when(pl.col('address').str.contains('NY'))
        .then(pl.lit('foodie'))
        .otherwise(pl.lit('elsewhere'))
        .alias('familiarity')
    ])

Test 2

• convert name data to lowercase
• create new column called email_name and extract email before the @
• select columns that starts with name or end with name
• create a new column called same?
• if name and email_name is the same, then return yes
• otherwise return no

Tidyverse

df |>
  mutate(
    name = tolower(name),
    email_name = str_extract(email, "^([\\d\\w]+)@", group = 1)
  ) |>
  select(starts_with("name") | ends_with("name")) |>
  mutate(`same?` = case_when(
    name == email_name ~ "yes",
    TRUE ~ "no"))

## # A tibble: 6 × 3
##   name    email_name   `same?`
##   <chr>   <chr>        <chr>  
## 1 alice   alice        yes    
## 2 bob     bob          yes    
## 3 charlie charlie      yes    
## 4 ken     ken          yes    
## 5 steven  stephencurry no     
## 6 carlos  carlos       yes

Polars

df \
    .with_columns(
        [
        pl.col('name').str.to_lowercase(),    
        pl.col('email').str.extract(r'^([\d\w]+)@', group_index = 1)
        .alias('email_name')
        ]
    ) \
    .select([
        pl.col('^name|.*name$'),
        pl.when(
            pl.col('name') == pl.col('email_name')).then(pl.lit('yes'))
            .otherwise(pl.lit('no'))
            .alias('same?')
    ]
        )

Learnt that apparently we cannot use look forward or backward in polars. Such as .*(?=@) to capture the email_name

Group_by, Shift, Forward_Fill < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

• group by department column
• summarize by selecting name, new column salary_shift with conditions:
  • if the department only has 1 row of salary data, do not shift salary
  • if the department has more than 1 row of salary data, shift by -1 of salary column
  • reason: there was a mistake in entering data for those with more than 1 row of data, apparently the actualy salary data is 1 row more
• then forward fill the salary_shift with the number prior in the same group

Tidyverse

df |>
  group_by(department) |>
  summarize(
    name = name,
    salary_shift = case_when(
      n() == 1 ~ salary,
      TRUE ~ lead(salary)
    )
  ) |>
 fill(salary_shift, .direction = "down")

## Warning: Returning more (or less) than 1 row per `summarise()` group was deprecated in
## dplyr 1.1.0.
## ℹ Please use `reframe()` instead.
## ℹ When switching from `summarise()` to `reframe()`, remember that `reframe()`
##   always returns an ungrouped data frame and adjust accordingly.
## Call `lifecycle::last_lifecycle_warnings()` to see where this warning was
## generated.

## `summarise()` has grouped output by 'department'. You can override using the
## `.groups` argument.

## # A tibble: 6 × 3
## # Groups:   department [3]
##   department  name    salary_shift
##   <chr>       <chr>          <dbl>
## 1 Engineering Alice          50000
## 2 Finance     Charlie        30000
## 3 Finance     Carlos         30000
## 4 Marketing   Bob            20000
## 5 Marketing   Ken            40000
## 6 Marketing   Steven         40000

Polars

df \
.group_by('department') \
.agg(
    pl.col('name'),
    pl.when(pl.col('salary').len()==1).then(pl.col('salary'))
    .otherwise(pl.col('salary').shift(-1))
    .alias('salary_shift')) \
.explode('name','salary_shift') \
.with_columns(
    pl.col('salary_shift').forward_fill())

Apparently polars would turn the column into a nested dataframe (list) when grouped and can’t do fill when it’s in list? will have to unnest by explode before fill can be used. Unless of coure if you merge the fill in the same line when shifting, such as

df \
.group_by('department') \
.agg(
    pl.col('name'),
    pl.when(pl.col('salary').len()==1).then(pl.col('salary'))
    .otherwise(pl.col('salary').shift(-1))
    .forward_fill() 
    .alias('salary_shift'))

Is There An Easier Way to Unnest without Typing ALL of the columns in Polars?

Yes! I believe pl.col, pl.select, pl.filter all take a list of conditions. First create a list of columns you want to unnest, then use pl.col to select them.

dt = [pl.List(pl.Int64),pl.List(pl.String)]

df \
    .group_by('department', maintain_order=True) \
    .agg(  
        pl.col('name'),
        pl.col('salary_increase_percentage'),
        salary_shift = pl.when(pl.col('salary').count() == 1)  
            .then(pl.col('salary'))
            .otherwise(pl.col('salary').shift(-1))
    ) \
    .explode(pl.col(dt)) \
    .with_columns(
        pl.col('salary_shift').forward_fill()
    ) \
    .with_columns(
        new_raise = pl.col('salary_shift') * (1+pl.col('salary_increase_percentage')/100)
    )

Merge / Join < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

• Create another mock data with dataframe called df_dept with columns department and dept_id

Tidyverse

df_dept <- tibble(
  department = c("Engineering", "Marketing", "Finance"),
  dept_id = c(30, 25, 20)
)

Polars

df_dept = pl.DataFrame({
    "department": ["Engineering", "Marketing", "Finance"],
    "dept_id": [30, 25, 20]
})

• left_join df with df_dept
• create new column employee_id by pasting:
  • {dept_id}-{random 7 digit numbers}

Tidyverse

df |>
  left_join(df_dept, by = "department") |>
  select(name, dept_id) |>
  mutate(employee_id = map_chr(dept_id, ~paste0(.x, "-", sample(1000000:9999999, 1))))

## # A tibble: 6 × 3
##   name    dept_id employee_id
##   <chr>     <dbl> <chr>      
## 1 Alice        30 30-1694470 
## 2 Bob          25 25-1696036 
## 3 Charlie      20 20-4463080 
## 4 Ken          25 25-6942432 
## 5 Steven       25 25-3012223 
## 6 Carlos       20 20-8705991

Polars

import random

df \
    .join(df_dept, on="department") \
    .select(['name','dept_id']) \
    .with_columns(
        employee_id = pl.format(
          '{}-{}',
          'dept_id',
          pl.Series([
            random.randint(100000, 999999) for _ in range(len(df))
            ])
            )
    )

there is a function called map_elements in polars but the documentation stated that it’s inefficient, essentially using a for loop. I’m not entirely certain if list comprehension above is any more efficient. Another probably more efficent way of doing this is 2 separate process. The random number generation on another dataframe, then merge it.

To Dummies, Pivot_longer / Pivot_wider < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

• create dummy variables for department using name as index or id

Tidyverse

df |>
  select(name, department) |>
  pivot_wider(id_cols = "name", names_from = "department", values_from = "department", values_fill = 0, values_fn = length, names_prefix = "department_")

## # A tibble: 6 × 4
##   name    department_Engineering department_Marketing department_Finance
##   <chr>                    <int>                <int>              <int>
## 1 Alice                        1                    0                  0
## 2 Bob                          0                    1                  0
## 3 Charlie                      0                    0                  1
## 4 Ken                          0                    1                  0
## 5 Steven                       0                    1                  0
## 6 Carlos                       0                    0                  1

Polars – to_dummies

df \
    .select(['name','department']) \
    .to_dummies(columns = 'department') 

Polars – pivot

df \
    .select(['name','address']) \
    .with_columns(
        state = pl.col('address').str.extract(r'([A-Z]{2})$')
    ) \
    .select('name','state') \
    .pivot(on = 'state', index = 'name', values='state', aggregate_function='len') \
    .with_columns(
        pl.col(pl.UInt32).fill_null(0)
    ) 

Essentially, pivot_wider is Polars’ pivot. Whereas pivot_longer is Polars’ unpivot

Helpful Resources < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

• Polars Python API documentation
• Cheat sheet
• cookbook Polars for R

Lessons Learnt: < svg class="anchor-symbol" aria-hidden="true" height="26" width="26" viewBox="0 0 22 22" xmlns="http://www.w3.org/2000/svg"> < path d="M0 0h24v24H0z" fill="currentColor"> < path d="M3.9 12c0-1.71 1.39-3.1 3.1-3.1h4V7H7c-2.76.0-5 2.24-5 5s2.24 5 5 5h4v-1.9H7c-1.71.0-3.1-1.39-3.1-3.1zM8 13h8v-2H8v2zm9-6h-4v1.9h4c1.71.0 3.1 1.39 3.1 3.1s-1.39 3.1-3.1 3.1h-4V17h4c2.76.0 5-2.24 5-5s-2.24-5-5-5z">

• stringr::str_extract has the parameter group
• We cannot use look forward or backward in polars
• polars also has selector for looking at column names more efficiently
• lots of trial and error
• going to try doing pure Polars for a month! Wish me luck!

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