caret::createFolds() vs. createMultiFolds()
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Summary
Recently a user posted a question on Stackoverflow, asserting that caret::createFolds()
behaves differently than createMultiFolds()
. The questioner argued that while createFolds()
samples without replacement, createMultiFolds()
samples with replacement. Our analysis demonstrates that the two functions behave consistently, creating k
folds where each observation in the data frame participates in one of the k
hold out groups. That said, by default createFolds()
returns a list containing the indexes of held out observations for each fold, whereas createMultiFolds()
returns a list of observations included in each fold for each repetition.
Behavior of createFolds()
createFolds()
splits the data into k
folds. Output from the function is a list of observation indices that are held out from each fold, not the rows included in each fold. We can see this by creating a table of all the fold data using the mtcars
data frame as follows.
set.seed(123) folds <- createFolds(mtcars$am, k = 5) table(unlist(folds))
…and the output:
> table(unlist(folds)) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 27 28 29 30 31 32 1 1 1 1 1 1
If we use the returnTrain = TRUE
argument with createFolds()
, it returns the index of observations included in each fold, as illustrated in the other answer. For k = 5
, we expect each observation to be used in 4 of the folds, and confirm this with the following code.
set.seed(123) folds <- createFolds(mtcars$am, k = 5, returnTrain = TRUE) table(unlist(folds))
…and the output:
> table(unlist(folds)) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 27 28 29 30 31 32 4 4 4 4 4 4
Behavior of createMultiFolds()
The createMultiFolds()
function is used to to define resampling plans for studies with repeated k-fold cross validation. By default, createMultiFolds()
returns a list containing one element for each level of k=
and each repetition of times=
We can illustrate that each observation is used in 4 of the 5 folds as follows.
set.seed(123) folds1 <- createMultiFolds(y = mtcars$am, k = 5, times = 1) table(unlist(folds1))
…and the output:
> table(unlist(folds1)) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 27 28 29 30 31 32 4 4 4 4 4 4
Generating equivalent results with createFolds() and createMultiFolds()
Setting returnTrain = TRUE
with createFolds()
causes it to return the same output as createMultiFolds()
with times = 1
.
We can compare the contents of folds
and folds
with lapply()
and all()
as follows.
# compare folds to folds1 lapply(1:5,function(x){ all(folds1[[x]],folds[[x]]) }) [[1]] [1] TRUE [[2]] [1] TRUE [[3]] [1] TRUE [[4]] [1] TRUE [[5]] [1] TRUE
If we set times = 2
, we expect each observation to be included in 8 of the 10 folds.
set.seed(123) folds <- createMultiFolds(y = mtcars$am, k = 5, times = 2) table(unlist(folds))
…and the output:
> table(unlist(folds)) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 8 27 28 29 30 31 32 8 8 8 8 8 8
Conclusions
In both functions caret
uses sampling to ensure that each observation is included in the hold out group 1 time across the k
folds for each repetition of times =
, within the constraint that observations for each value of the dependent variable passed to the function are proportionally distributed in the in sample and out of sample components of each fold.
In the case of a small data set such as mtcars
, it’s not easy for the algorithm to split effectively, as we can see when we run tables to compare in sample / holdout vs. mtcars$am
.
set.seed(123) folds <- createFolds(mtcars$am, k = 5) table(unlist(folds)) lapply(folds,function(x){ holdout <- rep(FALSE,nrow(mtcars)) holdout[x] <- TRUE table(holdout,mtcars$am) }) $Fold1 holdout 0 1 FALSE 16 10 TRUE 3 3 $Fold2 holdout 0 1 FALSE 15 10 TRUE 4 3 $Fold3 holdout 0 1 FALSE 14 11 TRUE 5 2 $Fold4 holdout 0 1 FALSE 15 11 TRUE 4 2 $Fold5 holdout 0 1 FALSE 16 10 TRUE 3 3
Each fold contains 6 or 7 observations in the hold out set, with a minimum of 2 manual transmission cars (am = 1
) in each hold out set.
With default arguments, createFolds()
returns the indexes of held out observations rather than included observations. createFolds(x,k,returnTrain=TRUE)
behaves exactly the same as createMultiFolds(x,k,times=1)
.
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