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My favorite R data.table feature is the “by
” grouping notation when combined with the :=
notation.
Let’s take a look at this powerful notation.
First, let’s build an example data.frame
.
d <- wrapr::build_frame( "group" , "value" | "a" , 1L | "a" , 2L | "b" , 3L | "b" , 4L ) knitr::kable(d)
group | value |
---|---|
a | 1 |
a | 2 |
b | 3 |
b | 4 |
The data is some sort of value with a grouping column telling us which rows are related.
With the data.table
“:=
,by
” notation we can add the per-group totals into each row of the data as follows (the extra []
at the end is just the command to also print the results in addition to adding the column in-place).
library("data.table") dt <- data.table::as.data.table(d) dt[, group_sum := sum(value), by = "group"][] # group value group_sum # 1: a 1 3 # 2: a 2 3 # 3: b 3 7 # 4: b 4 7
The “by
” signals we are doing a per-group calculation, and the “:=
” signals to land the results in the original data.table
. This sort of window function is incredibly useful in computing things such as what fraction of a group’s mass is in each row. For example.
# build a fresh copy as last command altered dt in place dt <- data.table::as.data.table(d) dt[, fraction := value/sum(value), by = "group"][] # group value fraction # 1: a 1 0.3333333 # 2: a 2 0.6666667 # 3: b 3 0.4285714 # 4: b 4 0.5714286
In base R (or in a more purely relational data system) the obvious way to solve this requires two steps: computing the per-group summaries and then joining them back into the original table rows. This can be done as follows.
sums <- tapply(d$value, d$group, sum) d$fraction <- d$value/sums[d$group] print(d) # group value fraction # 1 a 1 0.3333333 # 2 a 2 0.6666667 # 3 b 3 0.4285714 # 4 b 4 0.5714286
We called the transform a “window function”, as that is the name that SQL uses for the concept. The SQL code to perform this calculation would look like the following.
SELECT group, value, value/sum(value) OVER ( PARTITION BY group ) AS fraction FROM d
And the popular package dplyr
uses the following notation for the same problem.
d %>% group_by(group) %>% mutate(fraction = value/sum(value)) %>% ungroup()
And, as always, let’s end with some timings. For a 1000000 row table with 10 additional irrelevant columns, and group ids picked uniformly from 100000 symbols: we see the various solutions take the following times to complete the task.
## solution milliseconds ## datatable_soln 384 ## base_R_lookup_soln 1476 ## dplyr_soln 3988
All packages are the current CRAN releases as of 2019-06-29. Timings are sensitive to number of row, columns, and groups. Note the data.table
time includes the time to convert to the data.table
class.Details on the timings can be found here.
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