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I’m writing a series of posts on various function options of the glmnet
function (from the package of the same name), hoping to give more detail and insight beyond R’s documentation.
In this post, we will focus on the standardize option.
For reference, here is the full signature of the glmnet
function:
glmnet(x, y, family=c("gaussian","binomial","poisson","multinomial","cox","mgaussian"), weights, offset=NULL, alpha = 1, nlambda = 100, lambda.min.ratio = ifelse(nobs<nvars,0.01,0.0001), lambda=NULL, standardize = TRUE, intercept=TRUE, thresh = 1e-07, dfmax = nvars + 1, pmax = min(dfmax * 2+20, nvars), exclude, penalty.factor = rep(1, nvars), lower.limits=-Inf, upper.limits=Inf, maxit=100000, type.gaussian=ifelse(nvars<500,"covariance","naive"), type.logistic=c("Newton","modified.Newton"), standardize.response=FALSE, type.multinomial=c("ungrouped","grouped"))
Unless otherwise stated, fit
will denote the output/result of the glmnet
call. The data matrix is denoted by
standardize
When standardize = TRUE
(default), columns of the data matrix x
are standardized, i.e. each column of x
has mean 0 and standard deviation 1. More specifically, we have that for each
Why might we want to do this? Standardizing our features before model fitting is common practice in statistical learning. This is because if our features are on vastly different scales, the features with larger scales will tend to dominate the action. (One instance where we might not want to standardize our features is if they are already all measured along the same scale, e.g. meters or kilograms.)
Notice that the standardization here is slightly different from that offered by the scale
function: scale(x, center = TRUE, scale = TRUE)
gives the standardization
We verify this with a small data example. Generate data according to the following code:
n <- 100; p <- 5; true_p <- 2 set.seed(950) X <- matrix(rnorm(n * p), nrow = n) beta <- matrix(c(rep(1, true_p), rep(0, p - true_p)), ncol = 1) y <- X %*% beta + 3 * rnorm(n)
Create a version of the data matrix which has standardized columns:
X_centered <- apply(X, 2, function(x) x - mean(x)) Xs <- apply(X_centered, 2, function(x) x / sqrt(sum(x^2) / n))
Next, we run glmnet
on Xs
and y
with both possible options for standardize
:
library(glmnet) fit <- glmnet(Xs, y, standardize = TRUE) fit2 <- glmnet(Xs, y, standardize = FALSE)
We can check that we get the same fit in both cases (modulo numerical precision):
sum(fit$lambda != fit2$lambda) # 0 max(abs(fit$beta - fit2$beta)) # 6.661338e-16
The documentation notes that the coefficients returned are on the original scale. Let’s confirm that with our small data set. Run glmnet
with the original data matrix and standardize = TRUE
:
fit3 <- glmnet(X, y, standardize = TRUE)
For each column fit2
and fit3
respectively, then we should have
i.e. we should have
# get column means and SDs X_mean <- colMeans(X) X_sd <- apply(X_centered, 2, function(x) sqrt(sum(x^2) / n)) # check difference for intercepts fit2_int <- coefficients(fit2)[1,] fit3_int <- coefficients(fit3)[1,] temp <- fit2_int - colSums(diag(X_mean / X_sd) %*% fit2$beta) max(abs(temp - fit3_int)) # 1.110223e-16 # check difference for feature coefficients temp <- diag(1 / X_sd) %*% fit2$beta max(abs(temp - fit3$beta)) # 1.110223e-15
The discussion above has been for the standardization of x
. What about standardization for y
? The documentation notes that when family = "gaussian"
, y
is automatically standardized, and the coefficients are unstandardized at the end of the procedure.
More concretely, let the mean and standard deviation of glmnet
on standardized y
gives intercept glmnet
on unstandardized y
will give intercept
Again, this can be verified empirically:
# get mean and SD of y y_mean <- mean(y) y_sd <- sqrt(sum((y - y_mean)^2) / n) # fit model with standardized y fit4 <- glmnet(X, (y - y_mean) / y_sd, standardize = TRUE) # check difference for intercepts fit4_int <- coefficients(fit4)[1,] temp <- fit4_int * y_sd + y_mean max(abs(temp - fit3_int)) # 1.110223e-16 # check difference for feature coefficients max(abs(y_sd * fit4$beta - fit3$beta)) # 8.881784e-16
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