Intermediate Tree 2
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This is a continuation of the intermediate decision tree exercise.
Answers to the exercises are available here.
If you obtained a different (correct) answer than those listed on the solutions page, please feel free to post your answer as a comment on that page.
Exercise 1
use the predict()
command to make predictions on the Train data. Set the method to “class”. Class returns classifications instead of probability scores. Store this prediction in pred_dec.
Exercise 2
Print out the confusion matrix
Exercise 3
What is the accuracy of the model. Use the confusion matrix.
Exercise 4
What is the misclassification error rate? Refer to Basic_decision_tree exercise to get the formula.
Exercise 5
Lets say we want to find the baseline model to compare our prediction improvement. We create a base model using this code
length(Test$class)
base=rep(1,3183)
Use the table() command to create a confusion matrix between the base and Test$class
Exercise 6
What is the number difference between the confusion matrix accuracy of dec and base?
Exercise 7
Remember the predict() command in question 1. We will use the same mode and same command except we will set the method to “regression”. This gives us a probability estimates. Store this in pred_dec_reg
Exercise 8
load the ROCR package.
Use the prediction(), performance() and plot() command to print the ROC curve. Use pred_dec_reg variable from Q7. You can also refer to the previous exercise to see the code.
Exercise 9
plot() the same ROC curve but set colorize=TRUE
Exercise 10
Comment on your findings using ROC curve and accuracy. Is it a good model? Did you notice that ROC prediction() command only takes probability predictions as one of its arguments. Why is that so?
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