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It’s been quite a while since my last post on Euler problems. Today a visitor post his solution to the second problem nicely, which encouraged me to keep solving these problems. Just for fun!
10! = 10 * 9 * … * 3 * 2 * 1 = 3628800, and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27. Find the sum of the digits in the number 100!
The 20th problem is a big number problem. As it’s getting late, I’ll cut to the chase and use the gmp package to calculate this big-number multiplication. It is meant to make my life much easier. The solution is very straightforward: convert to ‘bigz’s, then calculate as usual.
1 2 3 4 5 6 | require(gmp)
num.lst <- as.bigz(1:100)
product <- prod(num.lst)
dec.num <- strsplit(as.character(product), split = "")
result <- sum(as.numeric(unlist(dec.num)))
cat("The result is:", result, "\n") |
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