Machine Learning Ex3 – Multivariate Linear Regression
[This article was first published on YGC » R, and kindly contributed to R-bloggers]. (You can report issue about the content on this page here)
Want to share your content on R-bloggers? click here if you have a blog, or here if you don't.
Want to share your content on R-bloggers? click here if you have a blog, or here if you don't.
Part 1. Finding alpha.
The first question to resolve in Exercise 3 is to pick a good learning rate alpha.
This require making an initial selection, running gradient descent and observing the cost function.
I test alpha range from 0.01 to 1.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 | ##preparing data input. x <- read.table("ex3x.dat", header=F) y <- read.table("ex3y.dat", header=F) #normalize features using Z-score. x[,1] <- (x[,1] - mean(x[,1]))/sd(x[,1]) x[,2] <- (x[,2] - mean(x[,2]))/sd(x[,2]) x <- cbind(x0=rep(1, nrow(x)), x) x <- as.matrix(x) ##gradient descent algorithm. gradDescent_internal <- function(theta, x, y, m, alpha) { h <- sapply(1:nrow(x), function(i) t(theta) %*% x[i,]) j <- t(h-y) %*% x grad <- 1/m * j theta <- t(theta) - alpha * grad theta <- t(theta) return(theta) } ## cost function. J <- function(theta, x, y, m) { h <- sapply(1:nrow(x), function(i) t(theta) %*% x[i,]) j <- 2*sum((h-y)^2)/m return(j) } ## calculate cost function J for every iteration at specific alpha value. testLearningRate <- function(x,y, alpha, niter=50) { j <- rep(0, niter) m <- nrow(x) theta <- matrix(rep(0, ncol(x)), ncol=1) for (i in 1:niter) { theta <- gradDescent_internal(theta,x,y,m, alpha) j[i] <- J(theta, x, y, m) } return(j) } ## test learning rate. alpha=c(0.01, 0.03, 0.1, 0.3, 1) xxx=sapply(alpha, testLearningRate, x=x, y=y) colnames(xxx) <- as.character(alpha) require(ggplot2) xxx <- melt(xxx) names(xxx) <- c("niter", "alpha", "J") p <- ggplot(xxx, aes(x=niter, y=J)) p+geom_line(aes(colour=factor(alpha))) +xlab("Number of iteractions") +ylab("Cost J") |
alpha = 0.3 seems to be the best.
Part 2. Normal Equations.
to be continued…
Related Posts
To leave a comment for the author, please follow the link and comment on their blog: YGC » R.
R-bloggers.com offers daily e-mail updates about R news and tutorials about learning R and many other topics. Click here if you're looking to post or find an R/data-science job.
Want to share your content on R-bloggers? click here if you have a blog, or here if you don't.